For those interested here are the equations for the black hole generator. The three main pieces of information we are interested is the black hole’s mass M (in kilograms), the power output P (in Watts), and the time it will take to evaporate (basically, the safety margin) T (in seconds). If you know one, it is possible to obtain the other two:
P = 3.563 x 10^32 / M^2 = 6.838 x 10^21 / T ^ (2/3)
T = 8.407 x 10^-17 * M^3 = 5.654 x 10^32 / P ^ (3/2)
M = 2.283 x 10^5 * T ^ (1/3) = 1.888 x 10^16 / P ^ (1/2)
Rechecking the numbers it appears I actually made errors in calculating the black hole’s parameters in the previous post, so I went back and corrected them.