For those interested here are the equations for the black hole generator. The three main pieces of information we are interested is the black hole’s mass *M (*in kilograms*)*, the power output *P* (in Watts), and the time it will take to evaporate (basically, the safety margin) *T* (in seconds). If you know one, it is possible to obtain the other two:

*P* = 3.563 x 10^32 / *M*^2 = 6.838 x 10^21 / *T* ^ (2/3)

*T* = 8.407 x 10^-17 ** M*^3 = 5.654 x 10^32 / *P* ^ (3/2)

*M* = 2.283 x 10^5 * *T* ^ (1/3) = 1.888 x 10^16 /* P* ^ (1/2)

Rechecking the numbers it appears I actually made errors in calculating the black hole’s parameters in the previous post, so I went back and corrected them.

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